Electromagnetic induction and conductor

AI Thread Summary
A conductor moving through a uniform magnetic field can indeed have an induced EMF if there is a component of the magnetic field perpendicular to its motion. While Faraday's law states that a change in magnetic flux is necessary for EMF induction, the movement of the conductor can create a change in flux through an imaginary loop that includes both the moving conductor and stationary parts. The formula F=qvB sin(theta) illustrates how the magnetic field interacts with the conductor's motion, resulting in a current. Thus, even in a uniform magnetic field, the motion can lead to EMF generation under specific conditions. Understanding these principles clarifies the relationship between motion, magnetic fields, and induced EMF.
ViolentCorpse
Messages
190
Reaction score
1
Hello everyone,

One very basic thing about this phenomenon is not very clear to me. If a conductor moves in a region of uniform magnetic field, would it have an EMF induced across it? I'm confused because as per Faraday's law, a change in flux through the conductor is necessary for EMF to be induced in it but if the flux is everywhere the same in the region where the conductor is moving, there should be no change in flux through it and consequently, no EMF in it.

How much wrong am I?
 
Physics news on Phys.org
If a conductor moves in a region of uniform magnetic field, would it have an EMF induced across it?
If it has a component perpendicular to both motion and magnetic field, yes.

I'm confused because as per Faraday's law, a change in flux through the conductor is necessary for EMF to be induced in it but if the flux is everywhere the same in the region where the conductor is moving, there should be no change in flux through it and consequently, no EMF in it.
Think of an imaginary loop, with the moving conductor and some stationary part, completing the loop (and some hand-waving to maintain the connection). The flux through this loop will change.
 
  • Like
Likes 1 person
Remember the F=qvB sin (theta) formula... The electrons in the wire will be pushed by the m field resulting in current flowing the opposite direction... As mfb said,there only has to a component of the m field perpendicular to the velocity...
 
  • Like
Likes 1 person
I see.

Thank you!
 
Back
Top