Electromagnetic Waves Problem -

AI Thread Summary
The discussion focuses on calculating the electric field amplitude of a 200 MW laser pulse focused to a diameter of 2.0 micrometers, with the correct value determined as 2.19×10^11 V/m. For Part B, the user struggles to find the ratio of this electric field to that of the electric field binding an electron to a proton in a hydrogen atom, initially using an incorrect method. A suggestion is made to apply the standard electric field equation for a point charge, E=q/(4πε₀r²), to simplify the calculation. This approach is recommended as it directly relates to the electric field generated by the proton at the radius of the electron's orbit. The discussion emphasizes the importance of using the correct formula for accurate results in electromagnetic wave problems.
ashkash
Messages
31
Reaction score
0
A 200 MW laser pulse is focused with a lens to a diameter of 2.0 micrometers.

Part A:
What is the laser beam's electric field amplitude at the focal point?

Part B:
What is the ratio of this electric field to the electric field that keeps the electron bound to the proton of a hydrogen atom? The radius of the electron's orbit is 0.053 nm.


I was able to get Part A correct. I used I = P/A to find the intensity using the power and area and then used E = sqrt( (2* I) / (c * epsilon_0)) to find the amplitude of the electric field and I got a numerical value of 2.19×10^11 V/m.

Part B is where I need help. I tried finding the electric field like I did in part A using the new radius given (0.053 nm) and then divided my answer from part A by this to get the ratio, but this does not work. What am I doing wrong?
 
Physics news on Phys.org
You got the hard part! Part B is much simpler. Use the standard electric field equation for a point charge: E=q/(4pi epsilon r^2)
 
thanks for the help.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top