Electromagnetism, find magnitude and direction of the resulting force on wire.

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A long straight wire carrying a current of 70 amperes east is placed in a uniform magnetic field of 0.15 T directed north. The force on a 25m length of the wire is calculated using the formula F=ILB sin θ, resulting in a force of 262.5 N. This force acts towards the right, which is perpendicular to both the current direction and the magnetic field. The direction of the force can be confirmed using Fleming's left-hand rule. The calculations and direction appear to be correct based on the given parameters.
RaDitZ
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A long straight horizontal wire carries a current of 70 amperes towards the east. The wire is placed in a uniform magnetic field of intensity 0.15 T towards the north.

Find the magnitude and direction of the resulting force on a 25m length of this wire



F=ILB sin \theta



F = 70*25*0.15sin 90

F = 262.5 N towards the right

Is it the right answer?
 
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The force should be perpendicular to east and north. Using Flemming's left hand rule find the direction.
 
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