Electromotive Force: E=Vab=IR Explained

In summary, the potential difference between the ends of a wire is given by Vab = IR. When combined with E = Vab, we can determine that E = Vab = IR for an ideal source of emf. This means that as positive charge flows through the circuit, the potential rise as it passes through the ideal source is equal to the potential drop as it passes through the remainder of the circuit. This is because the ideal source and the remainder of the circuit are connected to the same two nodes. This concept is also known as Kirchhoff's voltage law.
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AGGENGR
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The potential difference between the ends of a wire is given by Vab = IR. Combing that with E = Vab we have
E = Vab = IR (ideal source of emf).

" That is, when a positive charge flows around the circuit, the potential rise as it passes through the ideal source is numerically equal to the potential drop as it passes through the remainder of the circuit. Once and are known, this relationship determines the current in the circuit."- I can't seem to understand what this means?
 
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Imagine going around a closed loop in the circuit. As charge goes through the resistor it drops down in potential. As it goes through the battery it rises in potential. Those two potentials are equal in magnitude.
 
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...the potential rise as it passes through the ideal source is numerically equal to the potential drop as it passes through the remainder of the circuit.

If you think about it this is because the "ideal source" and the "remainder of the circuit" are connect to the same two nodes...
KVL.png


See also Kirchhoff's voltage law.
 
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Thanks i seem to get it after reading these posts and rereading the chapter! :):):):):):):):):):):):):):):):):):):)
 
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I can explain this concept in simpler terms. Electromotive force (EMF) is a measure of the energy that is created per unit charge in a circuit. It is represented by the symbol E and is measured in volts (V). The equation E=Vab=IR shows that the potential difference (Vab) between the two ends of a wire is equal to the product of the current (I) and the resistance (R) in the circuit. This is known as Ohm's law.

When we combine this equation with the ideal source of EMF, we can see that the potential difference created by the ideal source is equal to the potential difference created by the rest of the circuit. This means that as a positive charge flows through the circuit, the potential will rise as it passes through the ideal source and then drop as it passes through the rest of the circuit. This relationship between the EMF, potential difference, and current helps us to determine the amount of current flowing through the circuit.
 

1. What is electromotive force?

Electromotive force (EMF) is the energy per unit charge that is converted from one form to another in an electrical circuit. It is measured in volts (V).

2. What is the equation for electromotive force?

The equation for electromotive force is E = Vab = IR, where E is the EMF, Vab is the voltage difference between the two points in the circuit, I is the current flowing through the circuit, and R is the resistance of the circuit.

3. How is electromotive force related to voltage?

Electromotive force is the potential difference between two points in an electrical circuit, and is measured in volts. It is the driving force that causes current to flow in a circuit.

4. What is the role of resistance in electromotive force?

Resistance is a measure of how much a material opposes the flow of electrical current. In an electrical circuit, resistance affects the amount of current that flows for a given voltage and determines the amount of EMF produced in the circuit.

5. How is electromotive force related to Ohm's law?

Ohm's law states that the current flowing through a conductor is directly proportional to the voltage applied and inversely proportional to the resistance of the conductor. This means that for a given resistance, an increase in voltage will result in an increase in current and EMF in the circuit.

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