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juggalomike
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Homework Statement
at some instant the velocity components of an electron moving between two charged parallel plates are vx = 1.20 105 m/s and vy = 3.70 103 m/s. Suppose that the electric field between the plates is given by Evec = (120 N/C) jhat.
(a) What is the electron's acceleration in the field?
-2.11*E13 m/s2 jhat Incorrect
(b) What is the electron's velocity when its x coordinate has changed by 1.4 cm?
1.20*E5 m/s ihat + -2.46*E6 m/s jhat Incorrect
Homework Equations
F=ma
F=E*Q
V*T=D
V_0+A*T=V_1
The Attempt at a Solution
Rearranging the above equations i get A=(E*Q)/M
so A=(120*1.6*10^-19)/(9.1*10^-31)=2.11*10^13 jhat in the negative direction
Because acceleration is in the J direction there is no Iforce, so I is constant. so for D=t*V or t=d/v t=.014m/1.2*10^5=1.17*10^-7
then V_F=V_I+A*T so V_F=3.7*10^3+-2.11*10^13*1.17^10^-7=-2.46*10^6
Yet all of my answers are incorrect, what am i doing wrong?