Electrons accelerated between two plates

  • Thread starter Thread starter thegroovyguru
  • Start date Start date
  • Tags Tags
    Electrons Plates
AI Thread Summary
Electrons are accelerated to 7.1 keV between two parallel plates with a magnetic field of 0.004 T directed along the y-axis. The problem involves calculating the coordinates of point K after the electrons travel a quarter of a circle. The user calculated the velocity of the electrons to be approximately 5 x 10^7 m/s using kinetic energy equations. A force calculation using the magnetic field and charge was also attempted. The discussion touches on collaboration in homework, highlighting differing views on academic integrity.
thegroovyguru
Messages
4
Reaction score
0

Homework Statement



Electrons are accelerated between points A and B to the energy of 7.1keV, see attachment. The coordinate system was selected to have the origin at the startup point A. The electrons enter an area between two parallel plates where the magnetic field is established by running a current through the coils. It has magnitude of 0.004T and pointed in the direction of the y axis. After making a quarter of a circle, they reach a certain point K in between the plates. Report the coordinates x,y and z (in centimetres) of the point K.

I'm not sure what to do beyond what I've done already...

Homework Equations


F=qVBsin(t)
F=q(vXB)
r=(mv/qB)
KE=1/2mv^2


The Attempt at a Solution



KE=1/2mv^2
v=sqrt((2(1.135x*10^-15)/9.1*10^-31)
v=5*10^7 m/s

F=Bqv
F=.004(1.602*10^-19)5*10^7
F=3.2*10^-14 N
 

Attachments

  • Q2.jpg
    Q2.jpg
    30.7 KB · Views: 422
Physics news on Phys.org
u must go to u of s hahah and your an idiot your going against the engineering ethics code
-Blake B
 
really dough brain? how is this different than you and your friends getting together to work on assignments?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top