Electrostatic energy of three charges

AI Thread Summary
The electrostatic energy of a system with two equal charges and a third charge placed between them is calculated, resulting in a total energy of -E. The negative electrostatic potential energy indicates that energy is released when the charges are brought into position, suggesting an attractive force on a test charge from infinity. There is a distinction between the potential energy of the configuration and the electric potential around it, which can be both positive and negative depending on the distance from the charges. The discussion clarifies that the term "electrostatic energy" refers to the energy stored in the system rather than voltage. Understanding these concepts is crucial for grasping the behavior of electrostatic systems.
Vibhor
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Homework Statement



Two equal charges of magnitude Q each are placed at a distance d apart .Their electrostatic energy is E. A third charge -Q/2 is brought midway between these two charges .The electrostatic energy of the system is now

A) -2E
B) -E
C) 0
D) E

Homework Equations



EPE = kq1q2/r

The Attempt at a Solution


[/B]
The question is quite simple and I have correctly found the answer which is -E i.e option B).

Now what is puzzling me is the signifance of negative electrostatic potential energy of this configuration . By definition of EPE , since energy of this configuration is negative then this means that when a unit test charge is brought from infinity towards the configuration, it experiences an attractive force .But from a far off point , the configuration should look like a net positive charge .Thus , configuration of these charges should repel test charge .

What is the significance of minus sign in the EPE of this configuration ?

Thanks
 
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Vibhor said:
By definition of EPE, since energy of this configuration is negative then this means that when a unit test charge is brought from infinity towards the configuration, it experiences an attractive force.
Are you sure about this?
 
vela said:
Are you sure about this?

I might be wrong . EPE is electric potential per unit charge . Electric potential is work done in bringing a unit positive charge from infinity to a point . Since EPE is negative ,negative work is done , in which case the force is attractive from the configuration .

Please explain the mistake in my reasoning .
 
Vibhor said:
I might be wrong . EPE is electric potential per unit charge . Electric potential is work done in bringing a unit positive charge from infinity to a point . Since EPE is negative ,negative work is done , in which case the force is attractive from the configuration .

Please explain the mistake in my reasoning .
You confuse potential energy of a configuration with the potential around a configuration. The potential at a point P is the potential energy of a unit positive charge placed at that point. In this case, it can be both positive and negative. Far away, it is positive. Close enough to the negative charge, it is negative.
The potential energy of the configuration is equal to the work needed to make it. Negative energy means that energy is released when the three charges are brought into the positions given.
 
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ehild said:
Negative energy means that energy is released when the three charges are brought into the positions given.

o:) You are right .

In what manner is energy released when the charges are brought to their positions ?
 
ehild said:
You confuse potential energy of a configuration with the potential around a configuration. The potential at a point P is the potential energy of a unit positive charge placed at that point. In this case, it can be both positive and negative. Far away, it is positive. Close enough to the negative charge, it is negative.
The potential energy of the configuration is equal to the work needed to make it.
Vibhor said:
o:) You are right .

In what manner is energy released when the charges are brought to their positions ?
The charge is attribute of material bodies. So those charges can be charged little balls, for example. If you fix the two positive ones, and release the negative one far away, along the symmetry axis of the other two, it will move towards the positive ones by itself, and the kinetic energy increases during its journey, When it is at d/2 position you catch it and fix it, but the KE is used up somehow. For example, you can stop it by a spring. Or it will hit a hole in your hand :)
 
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Thanks
 
ehild said:
The potential at a point P is the potential energy of a unit positive charge placed at that point.
In the problem statement, does electrostatic energy refer to the energy stored in the system, or the voltage?

I think the term "potential" may signify either potential energy or potential difference (voltage), depending on the context.
 
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David Lewis said:
In the problem statement, does electrostatic energy refer to the energy stored in the system, or the voltage?
Yes !

Energy stored in the system.
 
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