Electrostatic Field and Particle Motion: Homework Solution and Explanation

In summary, the conversation discussed the electric field and forces between two small identical spheres carrying positive charges +q C. Along the line LM, the electric field varies due to repulsion between the charges, while along the line AB, there is no electric field due to the spheres being positioned between the charges. The acceleration and velocity of a positively charged particle initially at rest on LM close to one of the charges will change as the particle moves away, with a decrease in potential energy and an increase in distance r. It is important to note that the equations posted in the conversation should be checked for accuracy and completeness.
  • #1
BoanviaFx
30
0

Homework Statement


Can someone confirm if I answered correctly?

Question: Two small identical spheres each carrying a charge, +q C, are placed on the line LM as shown in the diagram:
v2tg8x.jpg

Describe how the intensity and direction of the electric field produced by the two charges varies:
i) Along the line LM, and
ii) Along the line AB

b) Describe how the acceleration and velocity of a positively charged particle initially at rest on the line LM very close to one of the charges +q, changes as the particle moves away from the charge.

Homework Equations

The Attempt at a Solution


i) Since the charges are both positive there will be a repulsion and the electric field along LM will be vacant.
ii) As for the direction same applies since both of the fields collide, no fields will be present along line AB since it is positioned between the two spheres.

b) The velocity would change due to a decrease in potential energy, as the other charge moves away the distance r begins to increase. When r=infinity the potential energy would be equal to zero. P.E=K.E

As for the acceleration, since the mass is a constant the force between the two charges would decrease.
a=F/M
 
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  • #2
BoanviaFx said:
i) Since the charges are both positive there will be a repulsion and the electric field along LM will be vacant.
Vacant meaning zero ? No.

ii) As for the direction same applies since both of the fields collide, no fields will be present along line AB since it is positioned between the two spheres.
Again. No. Both fields will be present. The term "collide" isn't applicable to fields in this stage of your education. The fields are static.

b) The velocity would change due to a decrease in potential energy, as the other charge moves away the distance r begins to increase. When r=infinity the potential energy would be equal to zero. P.E=K.E
It says "Initially at rest". With "other charge" you mean the particle ? With "distance r" you mean what, exactly ? Do you realize X is also on the line LM ?

As for the acceleration, since the mass is a constant the force between the two charges would decrease.
a=F/M
Which two charges, exactly ? There are three of them in this story...PS the section 2. Relevant eqations is blank on my screen. But you do need equations for the filed. make sure they are correct and complete when you post them.
 

1. What is an electrostatic field?

An electrostatic field is a type of electric field created by stationary electric charges. It describes the force that a charged particle would experience if placed in that field. The strength of the electrostatic field is determined by the magnitude and position of the charges creating it.

2. How is an electrostatic field different from a magnetic field?

An electrostatic field is created by stationary electric charges, whereas a magnetic field is created by moving electric charges. Additionally, an electrostatic field acts on both stationary and moving charges, while a magnetic field only acts on moving charges.

3. How do particles move in an electrostatic field?

Particles in an electrostatic field will experience a force in the direction of the field. If the particle is positively charged, it will be pushed in the direction of the field, while a negatively charged particle will be pushed in the opposite direction. The magnitude of the force depends on the charge of the particle and the strength of the field.

4. What is Coulomb's Law and how is it related to electrostatic fields?

Coulomb's Law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. This law is fundamental to the understanding of electrostatic fields, as it helps to calculate the strength of the field between two charged particles.

5. How can I calculate the work done on a particle in an electrostatic field?

The work done on a particle in an electrostatic field can be calculated by multiplying the magnitude of the electrostatic force by the distance the particle moves in the field. This is because work is equal to the force applied multiplied by the distance over which the force is applied. In an electrostatic field, the force is constant, so the work done is simply the product of the force and distance.

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