Electrostatic force calculations

In summary: However, this would be corrected for when integrating the force over a surface. In summary, integrating the electric field and charge density over a surface will give you the force.
  • #1
MAEdwards
1
0
I am trying to calculate the forces in a system with a mix of conductive + dielectric components upon application of an AC potential. Frequencies are low enough that I need not consider magnetic field effects. I can solve equations to obtain the electric field, but at am a loss for force calculations. I am familiar with calculating the Maxwell stress tensor in purely capacitative systems. It is unclear to me whether I should be somehow incorporating conductivity as part of a complex dielectric constant and using this in the Maxwell stress tensor calculation or I should just use the regular dielectric constant.

If someone could suggest how I would go about this, even for a parallel plate system filled with a material with uniform conductivity and permittivity, I am sure I could carry it forward. I have looked through a number of basic textbooks, but find nothing to help me, but if anyone can refer me to one which answers my query I would be equally glad.

Many thanks,

Martin
 
Physics news on Phys.org
  • #2
MAEdwards said:
I am trying to calculate the forces in a system with a mix of conductive + dielectric components upon application of an AC potential. Frequencies are low enough that I need not consider magnetic field effects. I can solve equations to obtain the electric field, but at am a loss for force calculations. I am familiar with calculating the Maxwell stress tensor in purely capacitative systems. It is unclear to me whether I should be somehow incorporating conductivity as part of a complex dielectric constant and using this in the Maxwell stress tensor calculation or I should just use the regular dielectric constant.

If someone could suggest how I would go about this, even for a parallel plate system filled with a material with uniform conductivity and permittivity, I am sure I could carry it forward. I have looked through a number of basic textbooks, but find nothing to help me, but if anyone can refer me to one which answers my query I would be equally glad.

Many thanks,

Martin

This is a good question and I agree that you don't often see this discussed in textbooks, hence I'm also not sure of the best answer. However, I can help brainstorm a little, just by restating things you already know.

Electric field is force per unit charge. Hence, if you solve an electro-static problem (really quasi-static because of AC fields) like this, you will have a solution for both electric field and charge density (really surface charge density). So, you should be able to integrate the net force over a surface using electric field and charge density.

The surface charge density is not constant in time because there is current flow with an AC potential. The analysis can be simplified with sinusoidal analysis which gives rise to the concept of complex permittivity (or complex conductivity). This comes from ampere's law, hence it is needed to calculate the surface charge density via surface current density.

Of course, none of these types of calculations are easy, but assuming you actually solve the field problem, then I'm thinking you shouldn't need to go back and use complex permittivity to calculate force. It seems you should be able to calculate a sinusoidally varying force from electric field and surface charge density directly. This should just be an integration operation. For example, with a parallel plate, there will be a force between the surface charge density in the conductor and that in the dielectric. This would be easy to calculate for large area plates.

Basically, the difference between DC and AC is that AC will generate a phase shift between the applied potential and the responding surface currents in the conductors. This results in delays in the build up of charge. However, whatever the charges are at a particular point in time, it is those charges that will exert force. Hence, it seems the field and charge solutions already contain the information you need, at least based on your simplifying assumptions.

The end result could show a force which is actually out of phase with the applied potential.
 

1. What is electrostatic force?

Electrostatic force is the force that exists between two stationary, electrically charged particles. It is caused by the attraction or repulsion of the electric charges.

2. How is electrostatic force calculated?

The electrostatic force between two charged particles can be calculated using Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

3. What are the units of electrostatic force?

The SI unit of electrostatic force is Newtons (N), which is equivalent to kg*m/s2. In the CGS system, the unit is dynes (dyne), which is equivalent to g*cm/s2.

4. How does distance affect electrostatic force?

According to Coulomb's law, the force between two charged particles decreases as the distance between them increases. This means that the force is inversely proportional to the square of the distance.

5. Can electrostatic force be shielded?

Yes, electrostatic force can be shielded by using conductive materials. These materials work by redistributing the charges on their surface, thus canceling out the electrostatic force between the charged particles.

Similar threads

Replies
1
Views
752
Replies
21
Views
16K
  • Electromagnetism
Replies
2
Views
1K
  • Electromagnetism
Replies
7
Views
2K
  • Electromagnetism
Replies
8
Views
914
Replies
11
Views
861
Replies
21
Views
1K
Replies
3
Views
999
Replies
16
Views
1K
Replies
5
Views
1K
Back
Top