Electrostatic force on a parallel plate

AI Thread Summary
To find the force between parallel plates in a capacitor, the formula F=qE is not sufficient due to the need to account for the electric field's characteristics. The electric field E is typically derived from the charge density and is halved when considering the contribution from both plates. The discussion suggests using Coulomb's law or calculating the electric field from a single sheet of charge for clarity. There is confusion regarding the correct value of the electric field, indicating a need for a deeper understanding of the underlying principles. Accurate calculations are essential for determining the force exerted between the plates.
serverxeon
Messages
100
Reaction score
0
I'm tasked to find the force one parallel plate exert on the other plate in a capacitor.

somehow the force isn't just F=qE, where E=Q/2εA

What am I missing here?
 
Physics news on Phys.org
What am I missing here?
Erm - direction?

You can check by using another method ... i.e. Coulombs law for a point charge and add them up, or start with the electric field due to a sheet of charge by itself.
 
i mean, my solution is lacking so coefficient.
based on my (confused and vague) understanding, the electric field is actually 1/2 E or something?
 
Is it? Why not calculate the field?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
1
Views
881
Replies
18
Views
2K
Replies
26
Views
2K
Replies
4
Views
1K
Replies
3
Views
1K
Replies
5
Views
2K
Back
Top