Elementary row operations- Linear Algebra

lina29
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Homework Statement



Consider the following 3 row operations performed to a 4x3 matrix A used to transform it into matrix B:
E1: -4R1+R4-> R4
E2: R2<->R3
E3: (1/2)R4-> R4
From there I am asked to find E1, E2, E3.

The Attempt at a Solution



I assumed the identity matrix I would start out with was
1 0 0
0 1 0
0 0 1
0 0 0

and then by using E1 the matrix would become
1 0 0
0 1 0
0 0 1
-4 0 0

However, the answer was counted wrong. Am I approaching the question the wrong way or am I using the wrong identity matrix?
 
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The identity matrix is actually 4x4:
[1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1]
 
ohh thank you so much! I got the correct answers but why is the identity matrix a 4x4 when the original matrix is a 4x3?
 
Last edited:
lina29 said:
ohh thank you so much! I got the correct answers no but why is the identity matrix a 4x4 when the original matrix is a 4x3?

Because you perform row operations on an mxn matrix by multiplying on the left by an mxm matrix.

RGV
 
Ray Vickson said:
Because you perform row operations on an mxn matrix by multiplying on the left by an mxm matrix.

RGV

what he said.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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