Eletric force and gravitational force question

AI Thread Summary
To determine how many extra electrons are needed on Earth and the Moon to balance their gravitational attraction with electric repulsion, the problem requires applying Coulomb's law and Newton's law of universal gravitation. The ratio of extra electrons must reflect the radial dimensions of the two bodies, specifically 6.38 for Earth and 1.74 for the Moon. By equating the forces from both laws, the relationship k(6.38/1.74)q^2 = GmM can be established. Solving this equation will yield the required charge values for both bodies. The discussion concludes with a successful resolution of the problem, indicating a clear understanding of the concepts involved.
strawberrysk8
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Homework Statement



How many extra electrons would we have to place on Earth and moon so the electric repulsion between these bodies cancels their gravitational attraction? Assume that the numbers of extra electrons on the Earth and on the moon are in the same propotion as the radial dimensions of these bodies (6.38:1.74).

Homework Equations





The Attempt at a Solution

 
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strawberrysk8 said:

Homework Statement


How many extra electrons would we have to place on Earth and moon so the electric repulsion between these bodies cancels their gravitational attraction? Assume that the numbers of extra electrons on the Earth and on the moon are in the same propotion as the radial dimensions of these bodies (6.38:1.74).

Homework Equations





The Attempt at a Solution


How would you think to address the problem? Can you think of any relevant formulas?
 
F=kqq/r^2

F=GmM/r^2

Constants: k,G,m,M,r

what is q1 and q2?
 
strawberrysk8 said:
F=kqq/r^2

F=GmM/r^2

Constants: k,G,m,M,r

what is q1 and q2?

Don't forget the additional constraint from the OP that q_earth is 6.38 to q_moon's 1.74.

q__{earth}= 6.38/1.74 * q__{moon}

With all the parameters but charge determined then what do you suggest doing with the two equations?
 
set them equal to each other

kqq/r^2 = GmM/r^2

kqq = GmM

k(6.38/1.74)q^2 = GmM

solve for q(moon)

then solve for q(earth)

what is the extra electons?
 
oh! i got it! thank you for the advice :)
 
strawberrysk8 said:
oh! i got it! thank you for the advice :)

Congrats then and good luck.
 
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