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## Homework Statement

the question given is:

What would the reading on a bathroom scale be if a 60kg pupil was accelerated upwards at a rate of 3m.s

^{-2}

## Homework Equations

F=m(g-a)

F=ma

## The Attempt at a Solution

F=m(g-a)

F=60kg(10m.s

^{-2}-3m.s

^{-2})

F=600-180

F=420N which is equal to the force on the person

The reading on the scale is therefore (42kg + 60kg) or 102kg but this seems too high

Thanks for helping