Tulzz
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Hi!, I am studying for an introductory course in QED and Feynman Diagrams. Everything we see is like a first order approach and I am having some trouble understanding antiparticles in Feynman Diagrams:
Why is it that we put an antiparticle that is leaving as if it is entering the interaction??
This is:
We have the interaction term:
\bar{\Phi}\gamma^{\mu} \Phi A_{\mu}
From which I understood that \bar{\Phi} corresponds to the outgoing particle. Yet for antiparticles we draw them as entering.
Also, i don't fully understand why we use the adjoint (i.e: with \gamma^0 multiplying) as the outgoing particles. I thought we were calculating interactions elements for the Hamiltonian. I don't know where the \gamma^0 comes from.
Sorry for my english.
Why is it that we put an antiparticle that is leaving as if it is entering the interaction??
This is:
We have the interaction term:
\bar{\Phi}\gamma^{\mu} \Phi A_{\mu}
From which I understood that \bar{\Phi} corresponds to the outgoing particle. Yet for antiparticles we draw them as entering.
Also, i don't fully understand why we use the adjoint (i.e: with \gamma^0 multiplying) as the outgoing particles. I thought we were calculating interactions elements for the Hamiltonian. I don't know where the \gamma^0 comes from.
Sorry for my english.
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