Eliminate Parametric to Derive x and y in tan(t)+sec(t) and tan(t)-sec(t)

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x=tan(t)+sec(t) and y=tan(t)-sec(t)

I have to take the derivative, but it specifically states that I must eliminate the Parametric to do so (I think as a way to check we can do this...oops)

I was thinking that I could turn the x into:
x=sint+1/cost and then I could go from there, the only problem is that I have no idea where to go.

If anyone has any ideas that would help me get this into a trig identity so I can solve for t, I would love it!
 
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xy = ?
It's also helpful to know a few trig identities involving secant and tangent.
 


you can do that?
 


hmmm

good call. Thank you soooooooo much!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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