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Enantiomeric excess question

  1. Jun 7, 2005 #1
    If a natural product was isolated and was found to have an enantiomeric excess (ee) of 84% what would be the percentages of each enatiomer in the mixture?
     
  2. jcsd
  3. Jun 7, 2005 #2

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    Well, do you know the equation (or definition) of enantiomeric excess?
     
  4. Jun 7, 2005 #3
    think about it...

    how many possible enantiomers are there. hint: the number of possible enantiomers is the same for any compound.

    so...let's say that the enantiomers were 50:50 in a mixture. then, the excess would be 0. if it were a 40:60 mixture, then one of the enantiomers would be in 10% excess. notice that (60 - (100 - 60) ) / 2 = 10

    see the pattern here?
     
  5. Jul 8, 2010 #4
    Enantiomeric excess (ee) of 84%

    Then major isomer % = (100+84)/2 = 92 %

    %minor isomer = 100-92 = 8%

    regards
    kandasani
     
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