Energy and Momentum: Elastic Collision of 2 Trains

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SUMMARY

The discussion centers on an elastic collision between two trains, Thomas (2.5 kg) and Diesel (5.0 kg) moving at 0.60 m/s. Key calculations include determining total kinetic energy before and after the collision, velocities at minimum separation, and energy stored at that point. The force-separation graph indicates that the collision force increases from 15 N to 45 N, and the minimum separation distance is critical for calculating energy dynamics. The area under the force-separation graph is essential for determining energy storage during the collision.

PREREQUISITES
  • Understanding of elastic collisions in physics
  • Knowledge of kinetic energy calculations
  • Familiarity with force-separation graphs
  • Basic integration concepts for area under a curve
NEXT STEPS
  • Calculate total kinetic energy using the formula KE = 0.5 * m * v^2
  • Explore the concept of minimum separation in elastic collisions
  • Learn about force-separation graphs and their applications in collision analysis
  • Study the principles of energy conservation in elastic collisions
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators seeking to explain elastic collisions and energy conservation principles.

yummallory
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Homework Statement


Thomas the train and Diesel are involved in an elastic collision. A 2.5 kg Thomas is, at rest but is approached head-on by a 5.0 kg Diesel moving at 0.60 m/s. The force-separation graph for the ensuing collision is given: http://tinypic.com/r/2zyftae/7

a. What is the total kinetic energy before the collision? After?
b. What is the velocity of each train at minimum separation?
c. What is the total kinetic energy at minimum separation?
d. How much energy is stored at minimum separation?
e. What is the minimum separation distance between the trains? Hint: The energy temporarily stored at minimum separation equals a portion of the area under the above graph. The collision starts when the centers of the trains are separated by 0.03 m as shown on the above graph at which time the collision force is 15 N. But this force increases to 30 N and then eventually 45 N.
f. What is the magnitude of the force acting on each mass at minimum separation?


Homework Equations





The Attempt at a Solution


I have no idea how to even start these questions, so if someone could help me with at least some of them or show me how to start them that'd be great..thank you!
 
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hi yummallory! :smile:

surely you know how to do a. ? :confused:

for the rest, you have a force against distance graph,

so the area under it will be the integral of force times distance, which is … ? :wink:
 

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