Energy dissipated over time by resistors

AI Thread Summary
The discussion focuses on calculating the energy dissipated by resistors in a circuit with given values for resistances and voltage. The current through the circuit is determined to be 0.24 A. The participant attempts to find the power dissipated using the formula P = i²R for each resistor and sums them up. They arrive at a power dissipation of 4.4928 J/s and calculate the total energy dissipated over one minute to be approximately 269.568 J. A suggestion is made to verify the calculation of the equivalent resistance (Rnet) to identify any potential errors.
scarne92
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Homework Statement



In the figure below, R1 = 9.00 , R2 = 23.0 and the ideal battery has an emf = 12.0 V.

hrw7_27-71.gif


(a) 0.24 A

(b) How much energy is dissipated by all four resistors in 1.00 min?

The Attempt at a Solution



Not sure where I went wrong.

P = inet2Rnet

P = i12R2 + i22R2 + i32R2 + i42R1

P = (0.24)2(23)+(0.24)2(23)+(0.24)2(23)+(0.24)2(9)

P = (0.24)2(23+23+23+9)

P = 4.4928 J/s

P = dW/dt

4.4928 = dW/60s

dW = (4.4928)(60)

W = 269.568 J
 
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I suspect you calculated Rnet incorrectly, and I get something different for inet than you.

If you show how you calculated Rnet, we might be able to spot the error.
 
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