Energy from 110m Dam: Cv=4.2kJ/kg/°C

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To compute the energy per unit mass from a 110m dam, one must consider the potential energy of the water as it flows down. The specific heat capacity (Cv) of water is given as 4.2 kJ/kg/°C, but this is not directly relevant to calculating potential energy. Instead, the focus should be on the gravitational potential energy formula, which involves the height of the dam and the mass of the water. Participants emphasize the importance of showing attempted solutions for homework questions to receive assistance. Understanding the equations of work and energy is crucial for solving such physics problems effectively.
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Compute the energy per unit mass that could be obtained by letting the water flow over a 110m dam. Cv=4.2kJ/kg/degrees celsius
 
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Herbert, unfortunately that's not how things work here.

If you've got a homework question, you should post it in the appropriate forum along with your attempted solution.

People here aren't generally willing to do other peoples' homework for them, sorry.
 
herbert2 said:
Compute the energy per unit mass that could be obtained by letting the water flow over a 110m dam. Cv=4.2kJ/kg/degrees celsius

Thread moved to Intro Physics. As brewnog says, herbert, you must show us your attempt at solving the problem before we can offer you tutorial help.

What can you tell us about the equations of work and energy? How would you compute the potential energy involved with a 110m tall dam, and water moving from the top to the bottom of the dam?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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