Energy, magnitude of E & B, pressure from a laser

AI Thread Summary
The discussion revolves around calculating the energy of a Ti-sapphire femtosecond laser pulse, its peak magnetic induction (B), electric field (E), and wave pressure. The laser has an intensity of 10^22 W/cm² and is focused to a 1μm radius, resulting in an energy of 0.314 J. The relationship between intensity, electric field, and magnetic induction is clarified through the time-averaged Poynting vector and relevant equations. The average radiation pressure is derived from the energy density of the wave, indicating a connection between energy and pressure. The conversation emphasizes the need for integration and understanding of Gaussian distribution for accurate calculations.
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Homework Statement



A Ti-sapphire femtosecond laser (1fs= 10^-15s, λ≈0.8μm) has an intensity of 1022 W/cm2
when focused to a spot of 1μm radius. What is the energy of the laser pulse? What is the peak
magnetic induction B in Tesla and the electric field in V/m? What is the wave pressure in
atmospheres?

Homework Equations



P = \int I da = \frac{E}{\Delta t}
E=cB

The Attempt at a Solution



I've solved the first part
P = IA = 10^{22} \frac{W}{cm^2} \pi \left(1 \mu m\right)^2
= 3.14 \times 10^{14} W
E = .314 J

But what is the relationship of what was given to either ]E or B? The only equations I can find are sinusoidal with the assumption that E_0 or B_0 are known to find their values at a particular time. Would I take the pulse with the assumption that B and E = 0 and the beginning and end and the information of the wavelength to find the value it peaks at? Now that I'm thinking of that, I'd still need some sort of E_0 or B_0.
 
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Assuming you have done the first part correct (if the question suggests it, you may need to integrate a gaussian distibution to get the power instead of just using the area of a circle)... anyway, to answer your question. The irrandiance I relates to both the electric field E and the magnetic induction B through its definition as the time averaged Poynting vector:

<br /> I \equiv \left\langle S \right\rangle = \frac{c^2\epsilon_0}{2}\left\vert E_0 \times B_0 \right\vert<br />

So that:
<br /> I = \frac{c}{2\mu_0}B_0^2<br />
<br /> I = \frac{1}{2}c\epsilon_0 E_0^2<br />

The "average" radiation pressure is given by the energy density of the wave (note the units energy/volume and force/area are the same)

P = \frac{1}{2}\epsilon_0 E_0^2 (this will give answer in Pascals though using previous units)

Hope this helps...
 
That does help immensely thank you.
 
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