Energy of an damped/undriven oscillator in terms of time?

GreenTikiFire
Messages
2
Reaction score
0

Homework Statement



The Q asks to show that the time rate of change in mechanical energy for a damped, undriven oscillator is dE/dt=-bV^2.

Homework Equations



I assume you take the derivative of the total E eq, E=(1/2)mV^2 + (1/2)kx^2 but I'm unsure how to put the E eq into terms of t, like E(t).

The Attempt at a Solution



Would you have to punch in the pos eq [x(t)=(Ae^(-βt))cos(ωt-δ)] in for x, then its derivative in for V? and then takes that entire eq's derivative? Seems like it would be too much work and not enough concept.
 
Last edited:
Physics news on Phys.org
i can't seem to get it in the form dE/dt=-bV^2.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top