Energy problem dealing with heat extracted from cold air

[astru025]

Homework Statement

A heat pump requires 385 W of electrical power to deliver heat to your house at a rate of 2410 J per second. How many joules of energy are extracted from the cold air outside each second?

Homework Equations

COP= Qc / W . This was the only equation I could find.

The Attempt at a Solution

Any help would be nice! I tried the above equation but I turned out to be incorrect.

 

[Kishlay]

use this and find out the ans...

 

[haruspex]

What do you think happens to the electrical energy used by the pump?

 

[Chestermiller]

This is the same as an air conditioner that is cooling the outside and rejecting the heat to the inside. If the heat pump operates reversibly, then Q₁ is removed from the outside at temperature T₁, and Q₂ is added to the inside at temperature T₂. For a reversible process, such that ΔS of the surroundings = 0, \frac{Q_1}{T_1}=\frac{Q_2}{T_2}. Since T₁<T₂, Q₂>Q₁. The difference between Q₂ and Q₁ is the work done by the heat pump.