Energy pumped into a water rocket? (soda bottle rocket)

AI Thread Summary
The discussion focuses on calculating the energy in a water rocket system, specifically how to determine the "under pressure" energy in a 2L soda bottle when air is pumped in. Participants suggest using principles from gas laws, such as Boyle's or Charles' law, to relate pressure and temperature. There is an interest in measuring the temperature changes to calculate kinetic energy, but the discussion reveals a lack of concrete solutions so far. Suggestions include calculating the number of moles of air in the bottle and considering temperature changes, but practical measurement techniques are still being explored. Overall, the conversation seeks effective methods to quantify the energy dynamics in a water rocket setup.
Head_Unit
Messages
43
Reaction score
2

Homework Statement


So you're shooting off a water rocket, which has some water inside a 2L soda pop bottle. You're then pumping (for example, a bicycle pump) to compress more and more air inside to a higher pressure.


Homework Equations


Well, work = F*d. If you measure the stroke of the pump, and the force (ha ha, we pictured putting a bathroom scale on top of the pump handle), you could calculate that work. But you miss losses and heating through the system.

I'd prefer to think about the pressure in the bottle. From Boyle or Charles or one of those fellows, we can say P1/T1=P2/T2. If you have ambient temp and pressure, you could somehow measure or calculate the "under pressure" temperature.*

Temperature relates to energy (kinetic), and you can calculate the volume of the bottle.

So how can we calculate the new "under pressure" energy in the system??


The Attempt at a Solution


Ha, not much so far, that's why we need help. Can we calculate the moles and thus the number of molecules in the volume of the bottle, then multiply by delta temperature?

?



*ideas as to HOW welcome. So far we just pictured painting one side of the bottle black and using an infrared thermometer to read the temp.
 
Physics news on Phys.org
bump-no takers? Too much like Chemistry? Even WAG welcome...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top