Energy-related problem involving skiing up a hill

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The skier's problem involves calculating the maximum height reached on a hill with friction. The skier has a mass of 68kg and approaches the hill at 15m/s, with the hill sloping at 40 degrees and coefficients of friction of 0.75 and 0.25. The work-energy theorem is suggested to solve the problem, where the final energy equals the initial energy plus work done against friction. To calculate work, the displacement along the slope can be expressed as s = y / sin(40 degrees), allowing for an equation with one unknown, the height y. This approach provides a clear path to finding the solution.
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Homework Statement


A 68kg skier approaches the foot of a hill with a speed of 15m/s. The surface of the hill slopes up at 40 degrees above the horizontal and has the coefficients of static and kinetic friction of 0.75 and 0.25, respectively. Use energy conservation to find the maximum height above the foot of the hill that the skier will reach.


Homework Equations


Conservation of energy, work-energy theorem



The Attempt at a Solution


I have no idea how to solve this question; since there is friction present in the system I decided to use the work-energy theorem, thus making: Ef = Ei + W, or mgh = (1/2)mv^2 + W. The problem I'm running into is trying to figure out how to calculate a value for W seeming as there are no displacement values given in the question. How would I go about getting an answer for W, or is this the wrong way to go about this question? Any help would be greatly appreciated, thanks in advance.
 
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Call the height that you are looking for y. The displacement along the hillside (for purposes of calculating work) is s = y / sin40o. So if you use the work energy theorem, you will have an equation involving only one unknown, y.
 
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