Energy released by condensing steam back to liquid water

AI Thread Summary
The energy lost from not condensing the steam is equivalent to the energy required to vaporize the water, which is 42.9 MJ for 19 kg of water. The latent heat of water is 2260 kJ/kg, indicating that the total energy loss can be calculated by multiplying this value by the mass of the water. If the process were 100% efficient and the water was pure and at boiling point, this would hold true. However, real-world conditions may affect efficiency, but this does not alter the calculation for the energy lost. The discussion emphasizes the theoretical energy loss based on ideal conditions.
corydm
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Homework Statement


vaporized 19 kg of water and did not capture and condense it. It took 42.9 MJ to vaporize the water, how much energy did I lose from not condensing the steam?

Homework Equations


Latent Heat of Water = 2260kJ/kg

The Attempt at a Solution


Would the energy lost to not capturing the condensation be the equivalent to the energy needed to vaporize the water?
 
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If your initial water was completely pure, directly at the boiling point and your process was 100% efficient, probably. I doubt that for realistic setups, especially the last part. Anyway, you don't have to care about that to find the answer.
 
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