How much energy can be stored in a spring with k = 400N/m if the maximum possible stretch is 12cm?
U = 1/2k(x^2)
The Attempt at a Solution
I tried using the above equation. U = 1/2(400)(.12^2) = 2.88.
what units should you use for the stored energy? (You left them out).Well I tried the answer, and it was wrong. I don't know what other equation I would use.
OK try 2.88J or 2.9J (I'm not good at significant figures) and see if the computer buys it.It would be (N/m)(m^2) = Nm = J
Yes, I think you're right, webassign gets very picky.As far as sig figs go, I think it should be 3 Joules. We only know the spring constant to one significant digit.
Great, just when I learn how to do significant figures, the computer wasn't looking for 'em. That figures!Holy crap everyone! I am so sorry about this problem. I was just going to try entering 3, when I noticed that I didn't put the decimal point into my original answer. BIG difference between 288 and 2.88! Sorry again!