Energy stored in the magnetic field of two inductors

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SUMMARY

The discussion focuses on calculating the energy stored in the magnetic field of two solenoids, A and B, with 400 and 700 loops respectively. Solenoid A carries a current of 3.5 amps, producing a self-flux of 300 microWebers and a mutual flux of 90 microWebers on solenoid B. The energy stored in the magnetic field is derived from the equation \( U = \frac{1}{2} L I^2 \), where L is the self-inductance. The user seeks clarification on the self-inductance value when considering mutual induction effects.

PREREQUISITES
  • Understanding of solenoid physics and magnetic fields
  • Familiarity with the concept of self-inductance and mutual inductance
  • Knowledge of the formula for energy stored in an inductor
  • Basic principles of electromagnetism
NEXT STEPS
  • Research the calculation of self-inductance for solenoids
  • Study the principles of mutual induction between coils
  • Learn how to apply the energy storage formula \( U = \frac{1}{2} L I^2 \) in complex circuits
  • Explore practical applications of inductors in electrical engineering
USEFUL FOR

Students studying electromagnetism, electrical engineers working with inductors, and anyone interested in the principles of energy storage in magnetic fields.

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Homework Statement


Two solenoids on the same cylindrical axis
Solenoid A has 400 loops and a current of 3,5 amp. Produces a flux of 300microWb on itself and 90 microWb on solenoid B
Solenoid B has 700 loops

Homework Equations


Calculate the energy stored in the system.

The Attempt at a Solution


Well, I know that the energy stored in magnetic field equals the square of the field over two times mu zero, but that's not the case here since I don't have the field.
I also know that for a self-inductor the energy stored equals to the square of the current times the self induction over two.
I believe I need to use that last equation, but as I don't understand where it comes from I don't know what to put as self-induction, or if it works also when the induction is produced by another coil.
 
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Did I do something wrong here not to get any answer?
 

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