Energy stored in the magnetic field of two inductors

AI Thread Summary
The discussion revolves around calculating the energy stored in the magnetic field of two solenoids, A and B, with different numbers of loops and currents. Solenoid A has 400 loops and a current of 3.5 amps, producing a self-flux of 300 microWebers and a mutual flux of 90 microWebers on solenoid B, which has 700 loops. The participant is unsure how to apply the formula for energy stored in a magnetic field due to a lack of information on self-inductance and its relationship to mutual induction. They express confusion about whether the energy formula for self-inductors applies when induction is influenced by another coil. The discussion highlights the complexities of inductance calculations in coupled systems.
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Homework Statement


Two solenoids on the same cylindrical axis
Solenoid A has 400 loops and a current of 3,5 amp. Produces a flux of 300microWb on itself and 90 microWb on solenoid B
Solenoid B has 700 loops

Homework Equations


Calculate the energy stored in the system.

The Attempt at a Solution


Well, I know that the energy stored in magnetic field equals the square of the field over two times mu zero, but that's not the case here since I don't have the field.
I also know that for a self-inductor the energy stored equals to the square of the current times the self induction over two.
I believe I need to use that last equation, but as I don't understand where it comes from I don't know what to put as self-induction, or if it works also when the induction is produced by another coil.
 
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Did I do something wrong here not to get any answer?
 

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