Enthelpy of transition of water to ice

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At a constant temperature of 258K and pressure of 1.000 atm, supercooled liquid water (2.00 mol) undergoes irreversible freezing, prompting a calculation of the change in enthalpy (ΔH). The specific heat capacities (Cp,m) for liquid water and ice are given as 75.48 KJ/mol and 37.15 KJ/mol, respectively. To calculate ΔH, a defined path is proposed: heating the supercooled water to 273K, freezing it, and then cooling the ice back to 258K. The discussion emphasizes the need to utilize known properties, such as the heat of fusion at 0C, to navigate the transition. This method effectively outlines the steps necessary to determine the enthalpy change during the phase transition.
Joel Martis
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1.At constant temperature of 258K and constant pressure of 1.000 atm , super cooled liquid water (2.00mol) freezes irreversibly. Find the change in enthalpy(ΔH) by assuming that Cp,m of liquid water and ice are 75.48 KJ/mol and 37.15KJ/mol and are constant. (this problem was from my assignment sheet so there might be errors in the units of Cp,m. By the way , Cp,m is the specific heat capacity at constant pressure.)



2.the only equation i could think of is ΔH=ΔU+ΔPV
 
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Hi Joel Martis. Welcome to Physics Forums.

In terms of the enthalpy and temperature, what is the defining equation for the heat capacity at constant pressure?

Chet
 
I think it is Cp,m= (∂H/∂T)p
 
Joel Martis said:
I think it is Cp,m= (∂H/∂T)p

Good. So now you have to define a path form the starting point to the final point along which you know all the properties needed to calculate the ΔH. The starting point is liquid water at -15C, and the end point is ice at -15 C. But, you only know the heat of melting/fusion at 0C. So, how do you get form the starting point to the final point if you only know the heat of fusion/melting at 0 C, and the heat capacities for the liquid water and the water ice?

Chet
 
Well, how about heating the supercooled water from 258K to 273K , freezing it, and then cooling the ice back to 258K?
 
Joel Martis said:
Well, how about heating the supercooled water from 258K to 273K , freezing it, and then cooling the ice back to 258K?

Sounds great.

Chet
 
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