Entropy Calculation in Thermodynamics Homework

AI Thread Summary
The discussion focuses on calculating the variation of entropy for two processes involving water: heating from 15 to 40ºC and compressing from ambient pressure to 7 atm. For the heating process, the specific heat capacity (Cp) of water is correctly identified as 4.18 kJ/kgºK, and the formula ΔS=Cp*ln(T_final/T_initial) is applied. However, for the compression process, the equation used is appropriate for ideal gases, not liquids, indicating a misunderstanding of the phase of water involved. The importance of considering internal energy changes, work done during compression, and heat transfer is emphasized for accurately determining entropy changes in liquids. Accurate calculations require using the correct equations for the state of water in each process.
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Homework Statement


Calculate the variation of entropy in the following processes:
a) Heating of 18 kg of water from 15 to 40ºC at ambient pressure.
b) Compression of 9 kg of water from ambient pressure to 7atm at the temperature of 15ºC.


Homework Equations


ΔS=Cp*ln(T_final/T_initial)

The Attempt at a Solution




So for a) I checked the Cp of water getting 4.18KJ/kgºK and multiplied it by the 18 kg. Then I tried to apply the formula with the Cp and the Tfinal=313.15K and TInitial=288.15K and I think it is correct.

For b) I think I have to use ΔS=R ln (P1 / P2) but I'm not sure. And if it is that expression, the Pressure must be in kPa?
 
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ruiwp13 said:

Homework Statement


Calculate the variation of entropy in the following processes:
a) Heating of 18 kg of water from 15 to 40ºC at ambient pressure.
b) Compression of 9 kg of water from ambient pressure to 7atm at the temperature of 15ºC.


Homework Equations


ΔS=Cp*ln(T_final/T_initial)

The Attempt at a Solution




So for a) I checked the Cp of water getting 4.18KJ/kgºK and multiplied it by the 18 kg. Then I tried to apply the formula with the Cp and the Tfinal=313.15K and TInitial=288.15K and I think it is correct.

For b) I think I have to use ΔS=R ln (P1 / P2) but I'm not sure. And if it is that expression, the Pressure must be in kPa?

In part (a) the equation you used applies to liquid water or to an ideal gas at constant volume. I assume you knew you were doing it for liquid water. The equation you used in part (b) is for an ideal gas, but not a liquid. The question must be referring to liquid water, because water can't exist as a vapor at these pressures and 15C. If the temperature doesn't change, what is the change in the internal energy of the liquid water? How much work is done on the water to compress it from 1 atm to 7 atm? How much heat is involved? What is the change in entropy?


Chet
 
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