Epsilon-delta definition and continuity at a point

[jameswill1am]

Homework Statement

Show that the following equation is continuous using the epsilon-delta definition at y=-2

Homework Equations

\f(y)=\sqrt[3]{y+3}

The Attempt at a Solution

so i got to a stage where;

\frac{1}{\left|\left(\sqrt[3]{y+3}\right)^{2}+\sqrt[3]{y+3}+1\right|}\times\left|y-c\right|

but this is where i always get stuck on these things. I just don't know where to start with picking my delta. If anyone could explain the best way of going about it that would be very helpful.

Thanks

p.s. i didn't type out the whole extent of my solution so far. Hopefully its ok so far but let me know if that bit is wrong as well.

 

[Mark44]

I revised your LaTeX so that it would render as you wanted it to.

Homework Statement

Show that the following equation is continuous using the epsilon-delta definition at y=-2

Homework Equations

f(y)=\sqrt[3]{y+3}

The Attempt at a Solution

so i got to a stage where;

\frac{1}{\left|\left(\sqrt[3]{y+3}\right)^{2}+\sqrt[3]{y+3}+1\right|}\times\left|y-c\right|

but this is where i always get stuck on these things. I just don't know where to start with picking my delta. If anyone could explain the best way of going about it that would be very helpful.

Thanks

p.s. i didn't type out the whole extent of my solution so far. Hopefully its ok so far but let me know if that bit is wrong as well.

I think I understand what you're doing, with the idea being that (a - b)(a² + ab + b²) = a³ - b³. I tried a different approach that I think will work.

I'm assuming you want to show that \lim_{y \rightarrow -2} f(y) - f(-2) = 0

This means you want to show that for any \epsilon > 0 there is a number \delta > 0 such that |f(y) - f(-2)| < \epsilon when |x - (-2)| < \delta
So given such an \epsilon, we want
|(y + 3)^{1/3} - 1| &lt; \epsilon
-\epsilon + 1 &lt; (y + 3)^{1/3} &lt; \epsilon + 1
(-\epsilon + 1)^3 &lt; y + 3 &lt; (\epsilon + 1)^3
(-\epsilon + 1)^3 - 1 &lt; y + 2 &lt; (\epsilon + 1)^3 -1

All that's left is to figure out what you need to use for your \delta.