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Equation for half-max contour of 2D Gaussian?

  1. Nov 29, 2012 #1
    Hi all,

    If I have a Gaussian with the equation:

    G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b)

    where x0, y0, a, b and h are the parameters which may vary, what's the equation for the elliptical contour line at the half-max of G?

    I'm getting myself confused!

    Thanks for help
  2. jcsd
  3. Nov 29, 2012 #2


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    How far did you get? Did you find the max value? Did you plug half that into the equation to see what resulted?
  4. Dec 3, 2012 #3
    I was wondering if there is some standard result that meant I didn't have to do all that.
  5. Dec 3, 2012 #4


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    G(x,y) = h/2 is what you want.

    (x-x0)2/a + (y-y0)2/b = ln2.
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