Equation for half-max contour of 2D Gaussian?

  • Thread starter mikeph
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  • #1
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Hi all,

If I have a Gaussian with the equation:

G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b)

where x0, y0, a, b and h are the parameters which may vary, what's the equation for the elliptical contour line at the half-max of G?

I'm getting myself confused!

Thanks for help
 

Answers and Replies

  • #2
haruspex
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G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b)
what's the equation for the elliptical contour line at the half-max of G?
How far did you get? Did you find the max value? Did you plug half that into the equation to see what resulted?
 
  • #3
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I was wondering if there is some standard result that meant I didn't have to do all that.
 
  • #4
mathman
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Hi all,

If I have a Gaussian with the equation:

G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b)

where x0, y0, a, b and h are the parameters which may vary, what's the equation for the elliptical contour line at the half-max of G?

I'm getting myself confused!

Thanks for help
G(x,y) = h/2 is what you want.

(x-x0)2/a + (y-y0)2/b = ln2.
 

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