Equation help with trig functions

AI Thread Summary
The discussion focuses on understanding the algebraic manipulation of the equation y = 4.0m + 4.0m(sin theta) and its equivalence to y = 4.0m(1 + sin(theta)). The key point clarified is that this transformation utilizes the distributive property, where 4 + 4(sin(theta)) can be factored as 4(1 + sin(theta)). Participants emphasize the importance of simplifying expressions by removing units to avoid confusion. The conversation also addresses common misconceptions about algebraic operations, particularly regarding the treatment of terms. Overall, the thread effectively explains the algebraic principles involved in the problem.
vysero
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I am currently working a physics problem and I have run into some math that I don't understand.

y = 4.0m + 4.0m(sin theta) = 4.0m(1+sin(theta))

In the problem I am trying to find a specific height at a certain angle (pendulum problem). I have found some help online that walks me through each step of the problem. I am just trying to understand how the above equation works, specifically the last part how 4 + 4(sin (theta)) is somehow equivalent to 4(1+sin(theta)). Is this some application of a formula or simple algebra that I am not understanding?

Maybe if you need more info you could check out the problem if you want too. The problem is located here: http://iweb.tntech.edu/murdock/books/v1chap6.pdf (Scroll down to page 143, worked examples # 6.2)
 
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vysero said:
I am currently working a physics problem and I have run into some math that I don't understand.

y = 4.0m + 4.0m(sin theta) = 4.0m(1+sin(theta))
This is nothing more than the distributive property.

a*b + a*c = a * (b + c)


vysero said:
In the problem I am trying to find a specific height at a certain angle (pendulum problem). I have found some help online that walks me through each step of the problem. I am just trying to understand how the above equation works, specifically the last part how 4 + 4(sin (theta)) is somehow equivalent to 4(1+sin(theta)). Is this some application of a formula or simple algebra that I am not understanding?

Maybe if you need more info you could check out the problem if you want too. The problem is located here: http://iweb.tntech.edu/murdock/books/v1chap6.pdf (Scroll down to page 143, worked examples # 6.2)
 
Okay so that's good to know. I am still a little confused. Why does the 4.0m turn into 1? For instance if I have (4+4)(x) I get 4x + 4x which equals 8x right? So maybe this is not the distributive property but if I have (4 +4)(sin(theta)) would that not be 4sin(theta) + 4sin(theta) which = 8sin(theta).. guess I still don't understand.
 
Here's a cleaned up version of what you write in post #1.
vysero said:
4 + 4sin(theta) = 4(1+sin(theta))

vysero said:
Okay so that's good to know. I am still a little confused. Why does the 4.0m turn into 1?
When you're doing algebra, you should get rid of the units. They don't add anything useful, and can cause confusion.

4 + 4sin(theta) = 4*1 + 4* sin(theta) = 4 * (1 + sin(theta))

Let's make it real simple, and get rid of the trig stuff.

4 + 4x = 4*1 + 4*x = 4(1 + x)
Get it?
vysero said:
For instance if I have (4+4)(x) I get 4x + 4x which equals 8x right? So maybe this is not the distributive property but if I have (4 +4)(sin(theta)) would that not be 4sin(theta) + 4sin(theta) which = 8sin(theta).. guess I still don't understand.
 
Awesome, thank you that's exactly what I needed to see.
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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