Equation of a curve passing through (1,2)

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SUMMARY

The discussion centers on finding the equation of a curve given its slope function, specifically 2x + 3, and a point it passes through, (1,2). The initial attempt incorrectly identified the equation of the tangent line at the point instead of the curve itself. The correct approach requires integration of the slope function to derive the curve's equation. The final equation of the curve is confirmed to be y = x² + 3x - 2.

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Homework Statement



A curve has slope 2x + 3 at each point (x, y) on the curve. Which of the following is an equation for this curve if it pases through the point (1,2)?

Answer: y= x2 + 3x - 2

Homework Equations



y= mx + b

The Attempt at a Solution



If the slope is 2x + 3, then that means it is the derivative. Since I a point (1,2), I can find m and b.

m = 2(1) + 3 = 5​

Thus,

2 = 5(1) + b
b = -3​

Therefore, my equation is

y= 5x - 3​

But this isn't correct. What am I doing wrong?
 
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You found the equation of the tangent to the curve at (1,2), not the equation of the curve.
 
vela said:
You found the equation of the tangent to the curve at (1,2), not the equation of the curve.

i agree.
To find the equation of the curve you will be doing some integration.
 

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