Equation of circle with arc length

AI Thread Summary
The discussion revolves around finding the values of 'a' and 'R' in the equation of a circle given specific x-intercepts and arc length above the x-axis. A participant initially attempts to solve the problem using the arcsine function but struggles to find a solution. Others suggest that a guess-and-check method, combined with diagram drawing, could lead to a quick resolution. The conversation highlights the balance between rigorous methods and practical approaches in solving mathematical problems. Ultimately, the participants emphasize the effectiveness of simpler techniques in reaching an answer.
Grand
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Homework Statement


Equation of a circle is:
x^2+(y+a)^2=R^2

x intercepts are +/-\sqrt{3} and arclength above x-axis is \frac{4\pi}{3}

Find a and R.
 
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Welcome to PF!

Hi Grand! Welcome to PF!

(have a square-root: √ and a pi: π and try using the X2 icon just above the Reply box :wink:)

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Hello, I've been tackling the problem for a while and the equation that I managed to come up with is:
\arcsin{\frac{\sqrt{3}}{R}}=\frac{4\pi/3}{2R}

I can't solve it, and haven't found anything else useful.
 
Hello Grand! :smile:

Yes, that looks good …

but it's obviously unsolvable without a computer, sooo :rolleyes:

hadn't you better assume the answer is really obvious, and just make a guess and see if it's right? :biggrin:
 
Well, is it? Even though it is stated in the book, I want to find a way to actually obtain it. Is there a way?
 
hmm :rolleyes: … computer, Newtonian approximation, bribing the TA … :wink:
 
Taylor was my guess too, but here we aim at an exact answer, so we should not use it. Even though, how would you guess the answer?
 
uhhh? :confused:

how many angles do you know with "√3" in the sine ? :smile:
 
Yeah, alright. But come on, there must be some rigorous way doing it - I've been solving it for couple of hrs now, even managed to prove Pythagoras with it.
 
  • #10
What's wrong with guess-and-check? It's a valid method. I don't mean to put you down, but combining this method with drawing a diagram, I was able to get the answer within minutes.
 
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