Equation of motion of magnetic dipole chain

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Homework Help Overview

The discussion revolves around finding the equation of motion for a one-dimensional chain of atoms with alternating magnetic dipoles. The original poster describes the setup where atoms of mass m are separated by a distance d, and small displacements from equilibrium are considered.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the net force on a particle due to dipole interactions and question the assumption of treating the atomic chain as connected by springs. There is discussion about the nature of the dipole arrangement and the forces involved, including whether the dipoles attract or repel each other.

Discussion Status

Participants are actively questioning the assumptions regarding the dipole arrangement and the forces at play. Some have provided insights into the linearity of the forces at small displacements and discussed the implications of the dipole interactions on the motion of the chain. There is no explicit consensus, but various interpretations and considerations are being explored.

Contextual Notes

There are mentions of the need for opposing forces for equilibrium, the arrangement of dipoles, and potential complications in the physical embodiment of the system, such as the stability of the alternating dipole configuration and the effects of repulsion on the chain's behavior.

throneoo
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Homework Statement


Find the equation of motion of a chain of atoms in 1D with alternating magnetic dipoles
At stationary equilibrium the atoms of mass m are separated by d , all displacements are small compared to d

Homework Equations


U=μBx=2μ20/4π)(1/x^3)
F(x)=-dU/dx

The Attempt at a Solution


The net force on particle n due to the dipole interactions
=F(xn-1-xn)-F(xn-xn+1)
However, I've found that if I fix the positions of the adjacent particles, the net force on particle n is a linear restoring force (with small displacement from eq. position). Can I assume that the atomic chain behaves as though they are connected by springs with identical fixed spring constant k? If so, the resultant equation would be

m*d2(xn)/dt2=-k*(2xn-xn-1-xn+1)
 
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I could use a fuller description of the set-up. Are the dipoles end-to-end, or (more likely) parallel?
Are we after end-to-end oscillations, lateral oscillations, or both?
For an equilibrium position to exist, don't there need to be opposing forces? Are the ends fixed, perhaps? Or some short-range repulsion?
 
haruspex said:
I could use a fuller description of the set-up. Are the dipoles end-to-end, or (more likely) parallel?
Are we after end-to-end oscillations, lateral oscillations, or both?
For an equilibrium position to exist, don't there need to be opposing forces? Are the ends fixed, perhaps? Or some short-range repulsion?
In a 1d infinite lattice with lattice constant d
the dipoles are assumed to be fixed in direction such that they are either end to end or head to head, so the nth particle will be repelled by the n-1 th particle and n+1 th particle in opposite directions. The particles are also assumed to be only affected by adjacent particles and oscillate longitudinally.

It turns out that I don't need to mentioned assumption in OP as I could directly obtain the form
m*d2(xn)/dt2=-k*(2xn-xn-1-xn+1)
from FNet ; n=F(xn-1-xn)-F(xn-xn+1) where xm=m*d+hm(t) and hm is the displacement from the eq. position of the mth particle
 
throneoo said:
In a 1d infinite lattice with lattice constant d
the dipoles are assumed to be fixed in direction such that they are either end to end or head to head, so the nth particle will be repelled by the n-1 th particle and n+1 th particle in opposite directions. The particles are also assumed to be only affected by adjacent particles and oscillate longitudinally.
Are you using 'particle' interchangeably with 'dipole', or is one dipole two particles?
If two dipoles are end to end in the same direction, won't they attract? Always?
I still don't see how you get from dipoles to springs. The force in a spring is proportional to the spring extension. Force between electric charges goes as the inverse square of distance and doesn't switch between attraction and repulsion.
 
haruspex said:
Are you using 'particle' interchangeably with 'dipole', or is one dipole two particles?
If two dipoles are end to end in the same direction, won't they attract? Always?
I still don't see how you get from dipoles to springs. The force in a spring is proportional to the spring extension. Force between electric charges goes as the inverse square of distance and doesn't switch between attraction and repulsion.
the particles are individual magnetic dipoles. they are arranged such they have alternating spins so they behave like bar magnets with same poles facing each other. The linearity of the force is only an approximation at small displacements from their eq. position
 

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throneoo said:
the particles are individual magnetic dipoles. they are arranged such they have alternating spins so they behave like bar magnets with same poles facing each other. The linearity of the force is only an approximation at small displacements from their eq. position
Ok, now I understand the arrangement, I see how you get the first order linearity.
Of course, each dipole has that sort of relationship to all the other dipoles, but it looks like this falls off as the inverse fifth power of distance, so maybe you only need consider adjacent ones.
Yes, that leads to the relationship you wrote in the OP, but I feel it would be more useful to write the right hand side as though n is a continuous variable. That should produce the usual wave equation.
What do you get for k in terms of the underlying constants (dipole strengths, spacing...)?

The physical embodiment of this arrangement still bothers me. What stops alternate dipoles flipping so that they all line up? What stops the whole chain expanding as the alternating dipoles repel each other? These considerations imply other forces, which would surely affect the wave behaviour.
 
haruspex said:
Ok, now I understand the arrangement, I see how you get the first order linearity.
Of course, each dipole has that sort of relationship to all the other dipoles, but it looks like this falls off as the inverse fifth power of distance, so maybe you only need consider adjacent ones.
Yes, that leads to the relationship you wrote in the OP, but I feel it would be more useful to write the right hand side as though n is a continuous variable. That should produce the usual wave equation.
What do you get for k in terms of the underlying constants (dipole strengths, spacing...)?

The physical embodiment of this arrangement still bothers me. What stops alternate dipoles flipping so that they all line up? What stops the whole chain expanding as the alternating dipoles repel each other? These considerations imply other forces, which would surely affect the wave behaviour.

I got k=6μ2μ0/πd5

and yeah I also feel the situation would be more complicated realistically
 
throneoo said:
I got k=6μ2μ0/πd5
Depending on what μ represents, I got the same.
 
  • #10
haruspex said:
Depending on what μ represents, I got the same.
The magnetic moment
 

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