Equation Questions for a gas powered engine driving a pulley system.

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To calculate the horsepower needed for a gas-powered engine driving a pulley system to drag a 400 lbs. object up a 45-degree incline for 150 feet, the required force is 1322 Newtons, equivalent to 297.19 Pounds Force. The desired speed for this operation is 3 miles per hour, which converts to 4.4 feet per second. Using the formula for horsepower, the calculation yields approximately 2.38 horsepower needed for this task. Additionally, torque calculations may be necessary, depending on the pulley system's design and configuration. Understanding these variables is crucial for ensuring the system operates efficiently.
andywingett
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I am building a prototype for an agricultural pulley system and I need help calculating how much horse power I need.

The pulley system will need to drag a 400 lbs. object of a 45 degree incline for 150 feet. The static coefficient of friction is 0.1 and the kinetic friction is only 0.05.

According to my calculations the Newtons of force needed to do this is 1322 = 297.19 Pounds Force.

I need to know how much horse power is needed to do this, and the amount of torque that will need to be exerted.

What are the other variables I need to input to solve this?
 
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How fast do you want to drag the object up the incline?
 
Three Miles per hour.
 
Horsepower = P * V / 550

For your case, V = [3 mph * 5280 ft/mi] / 3600 s/hr = 4.4 ft/sec.

1 hp = 550 ft-lbs/sec.

P = 297.19 lbs

horsepower = 297.19 * 4.4 / 550 = 2.38 hp
 

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