Equations for Accelerated Motion Problem

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SUMMARY

The problem involves a car accelerating from rest for 8 seconds, covering a distance of 121 meters. The average velocity was calculated as 15.125 m/s. Using the equation for acceleration, a = (2x)/t², the acceleration was determined to be 3.78 m/s². Finally, the final velocity was calculated using Vavg = (Vinital + Vfinal)/2, resulting in a final velocity of 30.25 m/s, confirming the correctness of the solution.

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Homework Statement



Starting from rest, a car accelerates for 8 seconds with a constat acceleration. During this time it travels 121 meters. Find its velocity at the end of the 8 seconds.

Homework Equations


a=(2x)t^2
Vavg=(Vinital+Vfinal)/2


The Attempt at a Solution


First, I found the average velocity by deviding 121 by 8 to get 15.125.

Second, (with instruction from my physics teacher), I found the acceleration.
a=(2x)*8^2
a=(2*121)/64
242/64=3.78
a=3.78 m/s


Then, knowing the acceleration, I found the final velocity.

Vavg=(0+Vfinal)/2
15.125=(Vfinal)/2
15.125*2=30.25 m/s
So, Vfinal should be 30.25 m/s, correct? I'm fairly sure of my answer, but I like to check before I turn it in.


Thanks in advance for a reply!:smile:
 
Physics news on Phys.org
seems good to me!...Answer is right.
 
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Likes   Reactions: 1 person
Thank you! You are so helpful.
 

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