Equations of Motion: Car Travels 60m/s for 10s

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A car traveling at an initial velocity of 60 m/s decelerates at -8 m/s². To calculate the distance traveled after 10 seconds, the relevant kinematic equation is S = ut + 1/2 at². Substituting the values into the equation yields the distance traveled. It's important to consistently use either the term "deceleration" or a negative sign, but not both simultaneously, to avoid confusion with acceleration. The correct application of these principles will provide the accurate distance traveled by the car.
failwhale
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A car with an initial velocity of 60m/s slows down with deceleration of -8m/s^2. How far will it have traveled after 10 seconds?
 
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Hi failwhale, welcome to PF.

Can you write down the relevant kinematic equations?
 
S = u.t + 1/2. a. t^2

substitute the value and find the answer, okay.

One more thing. either use word "deceleration" or use minus sign. don't use it together otherwise it is acceleration.
 

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