Equilibrium cylinder and plank on incline

AI Thread Summary
The discussion revolves around a physics problem involving a horizontal stick and a cylinder on an inclined plane. Participants analyze the free body diagram and the forces acting on the system, including normal and frictional forces. There is emphasis on ensuring that forces are accurately represented at the points of contact to avoid errors. A specific question arises regarding the direction of the friction force, with some confusion about why it points up the incline. The conversation highlights the importance of precision in diagrams and understanding force directions in static equilibrium problems.
joemama69
Messages
390
Reaction score
0

Homework Statement



A horizontal stick of mass m has its left end attached to a free pivot on a plane (inclined at angle θ), while it’s right end rests on a cylinder also of mass m which in turn rests on the plane, as shown. The coefficient of friction between the cylinder and both the stick and the plane is μ

(a) Assuming that the system is at rest, what is the normal force from the plane on the cylinder?

(b) What is the smallest value of μ (in terms of θ) for which the system doesn’t slip anywhere?


Homework Equations





The Attempt at a Solution



is my free body diagram correct on the attachment. I realize that the Ns and the us are differnt
 

Attachments

Last edited:
Physics news on Phys.org
Your free body diagram looks okay. I'd be a little more careful to make the normal forces and frictional forces perpendicular and locate them at the points of contact between the surfaces. I'd make mgcos(Q) perpendicular to the inclined plane, but then I'm a fussy old professor. I'd show the attachment of the horizontal stick to the pivot at the end of the inclined plane.

I guess you can summarize it by I'd be a little more complete and a little more careful. You cut down on errors that way. (Plus it impresses the person who grades your homework.)
 
I know this is from a few years ago, but can someone explain to me why that bottom friction force is pointed up the plane. It seems strange...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top