Equilibrium distance for solar sail

AI Thread Summary
The discussion focuses on determining the equilibrium distance for a solar sail where radiation pressure equals gravitational force. The user attempts to derive an equation but encounters a problem where the variables cancel out, leading to confusion about the existence of a specific equilibrium distance. It is clarified that both radiation pressure and gravity follow the inverse square law, suggesting that equilibrium can occur at all distances depending on the sail's mass-to-area ratio. The conversation concludes that achieving equilibrium requires the sail's areal density to be precisely balanced; otherwise, it will drift. This exploration highlights the complex interplay between forces acting on a solar sail in space.
cyberdiver
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This is not actually a homework assignment, but something I decided to try in my own time. I wanted to find the radius from a star at which a solar sail would be held at equilibrium (radiation pressure = gravity), given mass per unit area and stellar luminosity at a reference radius.

So I attempted the following:
Pressure of radiation and pressure of gravity are equal and opposing:
p_{radiation}=-p_{gravity}
Subsititute radiation pressure equation and gravity equation (rho_A is areal density, E_F is energy flux):
2 \cdot \frac{E_F}{c} = -{\rho}_A \cdot g
Substitute inverse square law equation into E_F, areal density equation into rho_A, and the law of universal gravitation equation:
2 \cdot \frac{E_{F0} \cdot (\frac{r_0}{r})^2}{c} = -\frac{m}{A} \cdot \frac{G \cdot M}{r^2}
Attempt to make r^2 the subject:
2 \cdot E_{F0} \cdot \frac{r_0^2}{r^2} \cdot A \cdot r^2 = -m \cdot G \cdot M

The problem here is that r^2 and r^2 will cancel out, making the equation useless. How else could I solve this problem? Does it require calculus?
 
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You are assuming there is a particular distance where a balance is struck. Your equations are telling you something else.
 
Hold on. Is it because radiation pressure and gravity both follow the inverse square law, so the equilibrium is at all distances?
 
cyberdiver said:
Hold on. Is it because radiation pressure and gravity both follow the inverse square law, so the equilibrium is at all distances?
Yes.
 
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But if the solar sail is heavy enough, it would start falling toward the star, wouldn't it?
 
cyberdiver said:
But if the solar sail is heavy enough, it would start falling toward the star, wouldn't it?
whether the sail drifts away from the star or falls towards it will depend on its mass to area ratio and the star's mass to flux ratio. What it won't depend on is the starting position.
 
So the sail can only reach a state of equilibrium if its areal density is just right, otherwise it would drift?
 
cyberdiver said:
So the sail can only reach a state of equilibrium if its areal density is just right, otherwise it would drift?
Yes.
 
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I understand now. Thank you very much!
 

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