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Equilibrium from the ceiling. Solve using cosines

  1. Jan 22, 2010 #1
    thanks
     
    Last edited: Jan 23, 2010
  2. jcsd
  3. Jan 22, 2010 #2

    Redbelly98

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    Where is the center of the rod located, relative to point B?
     
  4. Jan 22, 2010 #3
    I'm sorry!
     
    Last edited: Jan 23, 2010
  5. Jan 22, 2010 #4

    Redbelly98

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    Yes, I realize that the rod is opposite to angle B. The question was meant to give you a clue about the configuration. So more specifically, what do we know about where the center-of-mass of the hanging rod is located, relative to the point B from which the rod and strings are hung?
     
  6. Jan 22, 2010 #5
    I think the mg of the rod is located directly underneath point B where it is hung from the ceiling
     
  7. Jan 22, 2010 #6

    Redbelly98

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    Yes, exactly. You can use that information to figure out the angle the rod makes with the horizontal.
     
  8. Jan 22, 2010 #7
    Ok. so knowing that does angle B "split" into two halves. I am still not sure where this is taking me.!!
     
  9. Jan 22, 2010 #8

    Redbelly98

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    Draw a vertical line from B to the rod center. The triangle is split into two smaller ones. Solve either of the smaller triangles.

    Good luck!
     
  10. Jan 22, 2010 #9
    Ok thanks! I think i still need a little more guidance on this though. What will this solve? How will this help find theta?
     
  11. Jan 23, 2010 #10

    Redbelly98

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    The key is to find the triangle's angle located at the center of the rod. If you haven't already, draw a figure including the vertical line between B and the rod center.
     
  12. Jan 23, 2010 #11
    Ok. thanks
     
    Last edited: Jan 23, 2010
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