- #1
Hollysmoke
- 185
- 0
As you can see in the attachmen, I'm supposed to find the equilibriant force and the force from the left side.
So is it something like this:
Fx = 0,
Fh + 200cos20-100cos30=0
Fh = -101.33N
Fy = 0
Fv + 200sin20 + 100sin30 = 0
Fv = -118N
But I get stuck on the rest. Can someone help me out please?
So is it something like this:
Fx = 0,
Fh + 200cos20-100cos30=0
Fh = -101.33N
Fy = 0
Fv + 200sin20 + 100sin30 = 0
Fv = -118N
But I get stuck on the rest. Can someone help me out please?