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Equivalence factor or n factor (Equivalent weight)

  1. Mar 18, 2016 #1
    1. The problem statement, all variables and given/known data
    Equivalence factor of the salt is FeSO4.Cr2(SO4)3.24H2O is
    Ans is 8.

    2. Relevant equations


    3. The attempt at a solution
    Equivalence factor of an acid or base is its basicity or acidity, and for a compound undergoing redox reaction, it is the number of electrons exchanged per mole of compound. I'm not sure how to go about in the case of the given salt.
     
  2. jcsd
  3. Mar 18, 2016 #2

    Borek

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    Staff: Mentor

    Rather lousy question if you ask me. You can get 8 trying to precipitate hydroxides of both metals, but if you go for redox the more reasonable number is 7 (two Cr(III) get oxidized to Cr(VI) giving away 6 electrons, and Fe(II) gets oxidized to Fe(III) giving one electron, 6+1=7).

    In general, equivalents are often confusing when there is more than one reaction that can take place (which is why they should be avoided in the initial chemistry lessons).
     
  4. Mar 18, 2016 #3
    Ok thanks!
     
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