Equivalent Resistance in series-parallel circuit

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Discussion Overview

The discussion revolves around solving a homework problem related to finding the equivalent resistance in a series-parallel circuit. Participants share their attempts, methods, and challenges in arriving at the correct answer, with a focus on mathematical reasoning and the implications of significant figures.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses confusion about the homework problem and the lack of helpful notes, stating their attempt at a solution is close but still incorrect.
  • Another participant agrees with the first, suggesting that the discrepancy may be due to significant figures, indicating that the answer could be rounded to 2250 ohms.
  • A third participant confirms they are on the right track but highlights the challenge of online homework systems that require exact answers without partial credit.
  • One participant shares their own calculation, which rounds to 2247.6 ohms, aligning closely with the previous answers.
  • Another participant offers a different method for solving the problem, suggesting a visual approach using a specific equation format.
  • A later reply emphasizes the importance of mathematical accuracy in written work, cautioning against incorrect representations of values.

Areas of Agreement / Disagreement

Participants generally agree on the difficulty of the problem and the importance of significant figures, but there is no consensus on the exact method or final answer, as multiple approaches and calculations are presented.

Contextual Notes

Participants express uncertainty regarding the exact answer due to rounding and the constraints of the online homework system. There are also mentions of potential grading issues related to mathematical precision.

JustMerc
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Homework Statement


This is a sample problem. I'm trying to figure it out before I do the actual homework. The issue is, the way to figure it out is not included in our notes. I'm absolutely lost (math isn't my strong point) I've also included my attempt at how I think it should be done below, which got my really close. We're rounding to the nearest whole number, but I'm still off by 2. If it's hard to see: R1 = 2900 ohms, R3 = 800 ohms, Req = 3490 ohms. Find R2 in ohms.
Math126_Sample2.jpg


Homework Equations


The only equations given to us for equivalent resistance in series-parallel is GT = G1 + G2 and Rx = 1/GT which is really not helping to figure this out.

The Attempt at a Solution


Here's my attempt. I subtracted R1 from RT (590 or .001694915) and divided by 1. Then subtracted R3 (.00125) from that (.000444915). Divided by 1 and got within 2 of the answer after rounding (2248). I'm so lost on this.
attempt.jpg
 
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I got the same thing as you. If you're given that the answer is 2250, it's likely that it simply has to do with the significant figures. Either way, I'd say you're correct.
 
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So then I'm actually doing it correctly? The problem with that is, the homework is online. There's only one answer which works. If you're close...it's still wrong and there's no partial credit, because we don't show our work. Regardless to that fact, I appreciate you looking at it and leading me to believe I'm on the right path.
 
Agreed. I got 2247.6, which rounds to your answer.
 
BTW, a better, more visual way to do this problem is like this:

\frac{1}{\frac{1}{x}+\frac{1}{800}} = 590

Then put the two terms in the denominator over a common denominator, and solve for x. :-)
 
berkeman said:
BTW, a better, more visual way to do this problem is like this:

\frac{1}{\frac{1}{x}+\frac{1}{800}} = 590

Then put the two terms in the denominator over a common denominator, and solve for x. :)

Nice, thank you berkeman! Even though I couldn't get the answer (2250) on the sample question, I attempted the homework and thus far it is working. I appreciate the help from you all. It's not fun going into this stuff blindly.
 
When you turn in written work, do yourself a favor and don't write stuff like R3 = 800 = 0.00125 because because 800 doesn't equal 0.00125 and R3 isn't 0.00125 ohms. Chances are whoever is grading your work pays attention to mathematical detail and may find what you wrote irritating, and it's best not to irritate the grader.
 
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