Estimate minimum proton lifetime from internal radiation rate

AI Thread Summary
The discussion focuses on estimating the minimum proton lifetime based on internal radiation exposure. It establishes that a dose of 2 Greys per year would be lethal, and uses the mass-energy equivalence of protons to calculate decay frequency. The calculations suggest a decay frequency of approximately 10^11 years^-1, leading to a proton lifetime estimate on the order of 10^33 years. The relevance of water composition in the human body is noted, as it allows for estimating the number of protons based on water's molecular structure. Overall, the analysis highlights the relationship between radiation dose, proton decay, and human survival.
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Homework Statement


Estimate the minimum proton lifetime from the fact that you haven't yet died from internal radiation. Use the following conditions:
1.) At a dosis of Dmax = 2 Greys per year (Jkg-1 yr-1) you would already be dead.
2.) The human body is made mostly of water.
3.) The total proton mass of mp = 938 MeV/c2 is released during decay

Homework Equations


Dosis D = E/m
I am approx 60kg → m = 60kg

The Attempt at a Solution



maximum energy per year = Pmax = Emax / 1yr = Dmax m = 120 Jyr-1

decay frequency is therefore (maximum energy per year) / (total proton mass-energy) = f = 120 Jyr-1 / (1.6x10-19 JeV-1c2 * 938MeVc-2)

f ≈ 1011 yr-1
T ≈ 10-11 yr

order of magnitude should be T ≈ 1033yr.
and also where does the water element come into this I know H2O has a proton number Z = 10 but so, we are given the an energy limit to work this out and we can just divide this by the energy of one decay to get maximum number of decays? thanks
 
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You can estimate the amount of protons in your body if you assume you consist only of water.
 
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