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Homework Statement
Estimate the minimum proton lifetime from the fact that you haven't yet died from internal radiation. Use the following conditions:
1.) At a dosis of Dmax = 2 Greys per year (Jkg-1 yr-1) you would already be dead.
2.) The human body is made mostly of water.
3.) The total proton mass of mp = 938 MeV/c2 is released during decay
Homework Equations
Dosis D = E/m
I am approx 60kg → m = 60kg
The Attempt at a Solution
maximum energy per year = Pmax = Emax / 1yr = Dmax m = 120 Jyr-1
decay frequency is therefore (maximum energy per year) / (total proton mass-energy) = f = 120 Jyr-1 / (1.6x10-19 JeV-1c2 * 938MeVc-2)
f ≈ 1011 yr-1
T ≈ 10-11 yr
order of magnitude should be T ≈ 1033yr.
and also where does the water element come into this I know H2O has a proton number Z = 10 but so, we are given the an energy limit to work this out and we can just divide this by the energy of one decay to get maximum number of decays? thanks
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