Estimate the radiation pressure

AI Thread Summary
The discussion focuses on estimating radiation pressure from a 100 W bulb at a distance of 0.08 m and calculating the force on a fingertip with an area of 0.0001 m². The radiation pressure is derived using the formula Prad = P / (SA * c), where SA is the surface area of a sphere and c is the speed of light. The calculated radiation pressure is approximately 4.15 x 10^-6 Pa, leading to a force of about 4.15 x 10^-10 N on the fingertip. There is a mention of the fingertip's reflectivity affecting the results, suggesting that the absorbing case is assumed for the calculations. The calculations and approach are generally confirmed as correct, with a note on the fingertip's reflective properties.
ooohffff
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Homework Statement


a) Estimate the radiation pressure due to a 100 W bulb at a distance of .08 m from the center of the bulb.
b) Estimate the force exerted on your fingertip if you place it at this point. (Assume an area of .0001 m2 for the fingertip.)

Homework Equations


F=PradA

The Attempt at a Solution


a) I'm assuming the radiation is like a sphere. I'm a little confused on what radiation pressure formula to use in this situation. I have formulas for perfectly absorbing and perfectly reflecting?

Power = 100W
r = .08m
SA = 4πr2

b) I know that the Force = Pressure * Area of fingertip, so I would need to get a) right to get b)
 
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Would the equation be:

Prad = I / c ?

Plugging stuff in, this is what I get:

c = 1/√(μoεo)
I = P/ (SA)
Prad = P / ( (SA)*c ) = 100W/ (4π(.08)2*c) = 4.15*10-6 Pa

F= (4.15*10^-6 Pa) * (.0001 m2) = 4.15*10-10 N
 
ooohffff said:
I have formulas for perfectly absorbing and perfectly reflecting?
I would assume the absorbing case here. Please quote it.
 
ooohffff said:
Would the equation be:

Prad = I / c ?

Plugging stuff in, this is what I get:

c = 1/√(μoεo)
I = P/ (SA)
Prad = P / ( (SA)*c ) = 100W/ (4π(.08)2*c) = 4.15*10-6 Pa

F= (4.15*10^-6 Pa) * (.0001 m2) = 4.15*10-10 N
Looks right, except your fingertip will have some reflectivity.
 
haruspex said:
Looks right, except your fingertip will have some reflectivity.
Great thanks!
 
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