Estimate the velocity of each stone have just after the collision

AI Thread Summary
The discussion focuses on estimating the velocities of two curling stones after a collision, with stone A initially moving at 2 m/s before colliding with stationary stone B. After the collision, stone A moves at 1.5 m/s at an angle of 41.3 degrees, while the direction and velocity of stone B need to be calculated. Participants emphasize the importance of using conservation of momentum to analyze the collision and highlight that the presence of ice-sludge affects kinetic energy loss. The conversation also addresses the need for further information and resources to understand momentum and collision types better. Overall, the thread seeks clarity on the physics involved in the collision of the curling stones.
Newton86
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Hi :smile: I really need a answer to this task. Hope anyone can help.

A curling stone ( named A ) gets on the ice with a unknown beginning velocity Vo
the stone moves along a straight line ( x-axis ) on the x-axis further ahead lies another
stone ( named B ) still. Stone A collides with stone B in a sloped hit/knock
Just before the hit stone A has a velocity of 2m/s. After the slope stone A moves
straight with a angle of 45 degree in proportion at/of the x axis. Equivalently for stone B is -30 degrees.

a ) Estimate the velocity of each stone have just after the collision

b) Estimate the loss of kinetic energy in this collision. A curling stone have mass 20kg. what kind of collision is this ?


The reason for the energy loss is that big is that ice-sludge came between the stones in the collision. We clean up and retake the attempt. Now we reckon that the push is approximate perfect elastic Stone A has the velocity of 2 m/s before the push/hit and 1,5m/s after. The direction of a form the angle 41,3 degree with the x-axis after the push/hit.

c) Find the velocity and direction of B after the stone is Pushed/released.

d ) Check that the push of the stone is approximated elastic, by calculate the x component
 
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a) use conservation of momentum in the x and in the y direction.
 
Thanks. But can I get some moore information I am a noob :)
 
none ?
 
Newton86 said:
Thanks. But can I get some moore information I am a noob :)
What further information do your require?
 
Hootenanny said:
What further information do your require?

The formula and correct answer would been nice
 
Newton86 said:
The formula and correct answer would been nice
Nope, we don't do that here. Your going to have to do some work yourself. What can you say about the total momentum before and after the collision?
 
Hootenanny said:
Nope, we don't do that here. Your going to have to do some work yourself. What can you say about the total momentum before and after the collision?

Its less after the collition (velocity) ? Not sure what mometum means movement/direction or velocity ? But I am guessing its velocity
Im Not english:blushing:
 
Heres a good elementary resource: http://www.glenbrook.k12.il.us/GBSSCI/PHYS/CLASS/momentum/u4l1a.html
 
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But in a you don't know the mass
 
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