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Homework Statement
Homework Equations
The Attempt at a Solution
If 50% of the acid has been neutralised, then there is 0.05 M of acetic acid left.Using Ka
$$ 1.8*10^-5 = \frac {x^2}{0.05-x} $$
I get x = 0.00094
-log(0.00094) =3.02687 =pH
This is not one of the answers provided. I think I interpreted the question wrong. Can someone explain to me what I did wrong?
Cheers!