Evaluate integral of Sine function

In summary, the conversation is about a user who is new to a page and needs help with evaluating an integral. The integral is the Fourier transform of sin(pi*t/(2T)) over the limits of 0 to 2T. The user is familiar with doing the Fourier transform with limits of -infinity to infinity, but needs help with this specific limit. They then ask if the other user is familiar with Euler's identity and suggest rewriting the equation in a different form.
  • #1
muaythai2006
1
0
Hello guyz, I am new at this page. I need your help. I can't able to evaluate this integral. intergral of( sin(pi*t/(2T)) e^ -j2*pi*f*t)dt . The lower limit is 0 and the upper limit is 2T ...This is acctually the Fourier transform of sin(pi*t/(2T)) where 0<t<2T ...I could do the Fourier transform of this but only if the limit of t is -infinity to infinity...Thanks for your help...
 
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  • #2
Are you familiar with Euler's identity? Consider rewriting [tex] sin(\frac{ \pi t}{2T} ) [/tex] as [tex]\frac{1}{2j} (e^{\frac{j \pi t}{2T}} - e^{-\frac{j \pi t}{2T}})[/tex]

(Edit: Fixing the equation, LaTeX)
 
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1. What is the formula for evaluating the integral of a sine function?

The formula for evaluating the integral of a sine function is ∫sin(x)dx = -cos(x) + C.

2. How do you solve an integral of a sine function using u-substitution?

To solve an integral of a sine function using u-substitution, you first need to identify a part of the integral that can be represented as u. Then, you substitute u for that part and rewrite the integral in terms of u. After integrating, you can then substitute back for the original variable.

3. Can the integral of a sine function be evaluated using integration by parts?

Yes, the integral of a sine function can be evaluated using integration by parts. This method is useful when the integral involves a product of two functions, such as sin(x)cos(x).

4. Is the integral of a sine function always equal to zero?

No, the integral of a sine function is not always equal to zero. It depends on the limits of integration and the value of the constant C. If the integral is evaluated from 0 to 2π, the result will be 0. However, if the limits are different or if a non-zero constant is added, the result will be different.

5. Can the integral of a sine function be evaluated using trigonometric identities?

Yes, the integral of a sine function can be evaluated using trigonometric identities. For example, you can use the identity sin^2(x) + cos^2(x) = 1 to simplify the integral and make it easier to solve.

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