Evaluate integral of Sine function

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SUMMARY

The discussion focuses on evaluating the integral of the sine function, specifically the integral of sin(πt/(2T)) e^(-j2πft) dt from 0 to 2T. This integral represents the Fourier transform of sin(πt/(2T)). A key suggestion involves using Euler's identity to rewrite the sine function as (1/2j)(e^(jπt/(2T)) - e^(-jπt/(2T))). This transformation simplifies the evaluation of the integral within the specified limits.

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muaythai2006
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Hello guyz, I am new at this page. I need your help. I can't able to evaluate this integral. intergral of( sin(pi*t/(2T)) e^ -j2*pi*f*t)dt . The lower limit is 0 and the upper limit is 2T ...This is acctually the Fourier transform of sin(pi*t/(2T)) where 0<t<2T ...I could do the Fourier transform of this but only if the limit of t is -infinity to infinity...Thanks for your help...
 
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Are you familiar with Euler's identity? Consider rewriting [tex]sin(\frac{ \pi t}{2T} )[/tex] as [tex]\frac{1}{2j} (e^{\frac{j \pi t}{2T}} - e^{-\frac{j \pi t}{2T}})[/tex]

(Edit: Fixing the equation, LaTeX)
 
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