Evaluate Trig Sub Homework: Int from Infty to -Infty

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Homework Statement


Having trouble evaluating:
\int_{\infty}^{-\infty} \frac{dz}{(z^2+x^2)^(3/2)}

Homework Equations


Trig sub
z=xtan(\theta)

The Attempt at a Solution


comes down to:
\int_{x\frac{\pi}{2}}^{-x\frac{\pi}{2}} cos(\theta) d\theta
goes to
sin(\theta) from x\frac{\pi}{2} \longrightarrow -x\frac{\pi}{2}
ehh!?
 
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You can change the bounds differently. Think about it, as long x is some constant, and z approaching negative infinity and positive infinity, the tan theta has to be...
 
mm...just \frac{\pi}{2}
 
is that supposed to be to the 3/2 power or is that a constant multiplying the denominator?
 
rocophysics said:
is that supposed to be to the 3/2 power or is that a constant multiplying the denominator?
Sorry it is that quantity raised to the (3/2)
 
Basically I am trying to figure out how this book got
\frac{z}{x^2\sqrt(z^2+x^2)} with bounds from infinity to -infinity.
They then go on to get [1--1]=2.

I have to do this for a similar problem except my bounds will be L to -L.
the answer is: \frac{L}{x^2 \sqrt(L^2+x^2)} I do not know how.
Trying to remember how to do bounds on trig subs.
 
Anyone?
 
Winzer said:
Basically I am trying to figure out how this book got
\frac{z}{x^2\sqrt(z^2+x^2)} with bounds from infinity to -infinity.
They then go on to get [1--1]=2.

I have to do this for a similar problem except my bounds will be L to -L.
the answer is: \frac{L}{x^2 \sqrt(L^2+x^2)} I do not know how.
Trying to remember how to do bounds on trig subs.

maybe divide top and bottom by z. then plug in the limits from infinity to -infinity

I get zero? I get (1/x^2)-(1/X^2)
 
Winzer said:
Basically I am trying to figure out how this book got
\frac{z}{x^2\sqrt(z^2+x^2)} with bounds from infinity to -infinity.
They then go on to get [1--1]=2.

I have to do this for a similar problem except my bounds will be L to -L.
the answer is: \frac{L}{x^2 \sqrt(L^2+x^2)} I do not know how.
Trying to remember how to do bounds on trig subs.

Integrating with respect to z or x? State the exact question given to you please.
 
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